Post your Question in the comment section below.
3.9.1
passcode
#include
<stdio.h>
#include
<string.h>
#include
<stdbool.h>
#include
<ctype.h>
int
main(void) {
bool hasDigit = false;
char passCode[50] = "";
int valid = 0;
strcpy(passCode, "abc");
/* Your solution goes here */
if(isdigit(passCode[0]) ||
isdigit(passCode[1])|| isdigit(passCode[2])){
hasDigit=true;
}
if (hasDigit) {
printf("Has a digit.\n");
}
else {
printf("Has no digit.\n");
}
return 0;
}
3.9.2
whitespace
#include
<stdio.h>
#include
<string.h>
#include
<ctype.h>
int
main(void) {
char passCode[3] = "";
strcpy(passCode, "1 ");
/* Your solution goes here */
if(isspace(passCode[0]) &&
isspace(passCode[1])) {
passCode[0]='_';
passCode[1]='_';
}
else if(isspace(passCode[0])){
passCode[0]='_';
}
else if(isspace(passCode[1])) {
passCode[1]='_';
}
printf("%s\n", passCode);
return 0;
}
4.6.1
for loop
#include
<stdio.h>
int
main(void) {
int userNum
= 0;
int i = 0;
int j = 0;
/* Your solution goes here */
for(i=0;i<=userNum;i++){
for(j=1;i>=j;j++){
printf(" ");
}
printf("%d\n",i);
}
return 0;
}
4.6.2
for loop
#include
<stdio.h>
int
main(void) {
int numRows = 2;
int numCols = 3;
// Note: You'll need to define more
variables
int i=0;
int k=0;
char j='A';
for(i=1;i<=numRows;i++){
j='A';
for(k=1;k<=numCols;k++){
printf("%d%c ",i,j);
j++;
}
}
/* Your solution goes here */
printf("\n");
return 0;
}
5.2.2:
Printing array elements with a for loop.
#include
<stdio.h>
int
main(void) {
const int NUM_VALS = 4;
int courseGrades[NUM_VALS];
int i = 0;
courseGrades[0] = 7;
courseGrades[1] = 9;
courseGrades[2] = 11;
courseGrades[3] = 10;
for(i=0;i!=NUM_VALS;i++){
printf("%d
",courseGrades[i]);
}
printf("\n");
for(i=NUM_VALS-1;i>=0;i--){
printf("%d
",courseGrades[i]);
}
printf("\n");
/* Your solution goes here */
return 0;
}
